Feb 09
Topic : Area of Circle.
Question : A circle with area A1 is contained in the interior of larger circle with area A1+A2. If the radius of the larger circle is 3 and A1,A2,A1+A2 are in A.P,then the radius of smaller circle is__________.
Answer :
radius of the larger circle = 3
area of the larger circle = A1 + A2
A1+A2 = pi r^2 = 9 pi
A1+A2 = 9 pi —-(1)
A1, A2, A1+A2 are in A.P
hence the difference is common
A2 -A1 = A1 + A2 – A2 = A1
A2 = 2A1 —(2)
solving (1) and ( 2) ,
3A1 = 9 pi -> A1 = 3pi
Area of the smaller circle = 3 pi
radius of the smaller circle = square root of 3
(we have two concentric circles ; A1is the area of the inner circle , A2 is the area between the inner and outer circle)
Feb 05
Topic : parabola
Question : Growth rate y (in pounds/month)of an infant is related to the present weight x(in pounds)by formula y= cx(21-x)where c is a positive constant.0<x<21.At what rate does the maximum growth occur.
Answer :
The y coordinate of the vertex is the max of a quadratic if the parabola is downward and its the minimum if its upward.
the parabola is upward if the co efficient of x^2 is positive and downward if its negative.
here we have y= c x(21-x)= 21cx -c x^2
as the co efficient of x^2 is negative, we get a maximum value
formula: for y = ax^2+bx+c , the vertex is given by ( -b/2a , f( -b/2a) )
hence the maximum y value is -b/2a
here the max growth rate = – 21c / -2c = 21/2 =10.5pounds/month.